2x^2=62^2

Solution for 2x^2=62^2 equation:

2x^2=62^2

We move all terms to the left:

2x^2-(62^2)=0

We add all the numbers together, and all the variables

2x^2-3844=0

a = 2; b = 0; c = -3844;
Δ = b2-4ac
Δ = 02-4·2·(-3844)
Δ = 30752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30752}=\sqrt{15376*2}=\sqrt{15376}*\sqrt{2}=124\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-124\sqrt{2}}{2*2}=\frac{0-124\sqrt{2}}{4}
=-\frac{124\sqrt{2}}{4}
=-31\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+124\sqrt{2}}{2*2}=\frac{0+124\sqrt{2}}{4}
=\frac{124\sqrt{2}}{4}
=31\sqrt{2}
$